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Define acceleration , average acceleration and instantaneous acceleration.
Solution
The time rate of change of velocity is called acceleration.
Let a particle be moving in a straight line and at time $t_{1}$ and $t_{2}$ its velocities are $v_{1}$ and $v_{2}$ respectively. Thus, the change in velocity of the particle in time interval $\Delta t=t_{2}-t_{1}$ is $v_{2}-v_{1}$. According to definition of average acceleration,
$\text { Average acceleration }=\frac{\text { change in velocity }}{\text { time }}$
$\therefore\langle a\rangle=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}=\frac{\Delta v}{\Delta t}$
Average acceleration is a vector quantity and its direction is in the direction of change in velocity $(\Delta v)$.
Taking $\lim _{\Delta t \rightarrow 0}$ in equation then we get instantaneous acceleration $a$ at time $t$.
Similar Questions
For the velocity-time graph shown in the figure, in a time interval from $t=0$ to $t=6\,s$, match the following columns.
Colum $I$ | Colum $II$ |
$(A)$ Change in velocity | $(p)$ $-5 / 3\,Sl$ unit |
$(B)$ Average acceleration | $(q)$ $-20\,SI$ unit |
$(C)$ Total displacement | $(r)$ $-10\,SI$ unit |
$(D)$ Acceleration at $t=3\,s$ | $(s)$ $-5\,SI$ unit |